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Section 1.7 Inverse Functions

In this section, we’ll see what happens if you turn a function inside-out and make the output become the input and the input become the output. We’ll also explore when doing this will result in a function and what it means if it does.

Subsection Textbook Reference

This relates to content in §3.7 of Algebra and Trigonometry 2e
 1 
http://tiny.cc/111Z-Textbook
.

Exercises Preparation Exercises

1.

Consider the following set of ordered pairs:
\begin{equation*} \{ (\text{Alaska}, 1), ~ (\text{Washington},10), ~ (\text{Oregon},6), ~ (\text{Idaho}, 2),~ (\text{Nevada}, 4),~ (\text{Hawaii}, 2),~ (\text{California}, 52)\} \end{equation*}
(a)
Does this set represent a function? Answer by referencing the definition of a function.
(b)
If we were to swap the \(x\) and \(y\)-values, would this new set be a function? Explain your answer.
\begin{equation*} \{ (1, \text{Alaska}), ~ (10, \text{Washington}), ~ (6, \text{Oregon}), ~ (2, \text{Idaho}),~ (4, \text{Nevada}),~ (2, \text{Hawaii}),~ (52, \text{California})\} \end{equation*}

2.

The formula to convert a temperature \(F\) in degrees Fahrenheit to a temperature \(C\) in degrees Celsius is given by the function
\begin{equation*} C = g(F) = \frac{5}{9}(F-32) \end{equation*}
(a)
For each temperature in degrees Fahrenheit, how many temperatures in degrees Celsius are produced by this formula?
(b)
For each temperature in degrees Celsius, how many temperatures in degrees Fahrenheit are produced by this formula?
(c)
Would it be true to state that \(C\) is a function of \(F\) and also that \(F\) is a function of \(C\text{?}\) Why or why not?

Exercises Practice Exercises

1.

\(f\) is defined in the table below.
\(x\) \({-4}\,\) \({-2}\,\) \({0}\,\) \({2}\,\) \({4}\,\)
\(f(x)\) \({4}\,\) \({2}\,\) \({-2}\,\) \({-4}\,\) \({0}\,\)
Evaluate the following.
(a)
\(f(0)\)
(b)
\(f^{-1}(0)\)
(c)
\(f^{-1}(-4)\)

2.

\(y = g(x)\) is defined in Figure 1.7.1.
described in detail following the image
Graph of a smooth curve containing the points \((-1,5)\text{;}\) \((0,2)\text{;}\) \((1,1)\text{;}\) \((3,-1)\text{;}\) and \((5,-3)\text{.}\) The curve extends off of the graph to the left and right.
Figure 1.7.1. \(y=f(x)\)
Evaluate the following.
(a)
\(g(5)\)
(b)
\(g^{-1}(5)\)
(c)
\(g^{-1}(-1)\)

3.

(a)
Graph the function \(f(x) = 4 + \sqrt[3]{x-1}\) in a graphing utility (such as Desmos) to confirm that it is a one-to-one function and then find the formula for \(f^{-1}\text{.}\)

4.

Graph the function \(g(x) = 2 - \sqrt{x + 3}\) in a graphing utility.
(a)
Is \(g\) a one-to-one function? Why or why not?
(b)
State the domain and range of \(g\text{.}\)
(c)
Algebraically find a formula for \(g^{-1}\text{.}\)
(d)
State the domain and range of \(g^{-1}\text{.}\)

Subsection Definitions

Definition 1.7.2. One-to-One Function.

A function \(f\) is said to be one-to-one if for every possible output (\(y\)-value) in the range of \(f\text{,}\) there is exactly one input (\(x\)-value) in the domain of \(f\text{.}\)
In other words, in a one-to-one function, each possible input is paired with exactly one output AND each possible output is paired with exactly one input.

Example 1.7.3.

The set \(\{ (0,-2), ~ (1, \boldsymbol{-1}), ~ (4, 0), ~ (9,\boldsymbol{-1}),~ (16,-3) \}\) is a function, but it is not one-to-one.

Example 1.7.4.

The set \(\{ (0,-2), ~ (1, -1), ~ (2, 0), ~ (3, 1),~ (4,2) \}\) is a function and is one-to-one.

Definition 1.7.5. Horizontal Line Test.

If a horizontal line can be drawn that intersects the graph of a function more than once, the graph is not the graph of a one-to-one function.

Example 1.7.6.

described in detail following the image
Graph of an upward facing parabola with vertex \((-1,-4)\text{.}\) A horizontal line is drawn at \(y = -2\text{,}\) intersecting the parabola at the points \((-3,-2)\) and \((1,-2)\text{,}\) demonstrating the horizontal line text.
Figure 1.7.7. Does Not Pass

Example 1.7.8.

described in detail following the image
Graph of a function that passes the horizontal line test. The curve moves smoothly through the points \((-6,-1)\text{,}\) \((-2,1)\text{,}\) and \((7,4)\text{,}\) extending off of the graph in both directions. There is no \(y\)-value for which a line could be drawn that intersects the curve more than once.
Figure 1.7.9. Passes

Definition 1.7.10. Inverse Function.

If a function \(f\) is one-to-one, then the function has an inverse, \(f^{-1}\text{.}\)
Two functions \(f\) and \(f^{-1}\) are inverse functions if and only if both of the following are true:
  • \(f \left( f^{-1}(x) \right) = x\) for all \(x\) in the domain of \(f^{-1}\text{.}\)
  • \(f^{-1} \left( f(x) \right) = x\) for all \(x\) in the domain of \(f\text{.}\)
The domain of a function \(f\) is the range of the inverse function \(f^{-1}\text{.}\)
The range of a function \(f\) is the domain of the inverse function \(f^{-1}\text{.}\)

Example 1.7.11.

If \(f\) is defined by the set
\begin{equation*} \{ (0,-2), ~ (1, -1), ~ (2, 0), ~ (3, 1),~ (4,2) \}, \end{equation*}
then \(f^{-1}\) is the set
\begin{equation*} \{ (-2,0), ~ (-1, 1), ~ (0, 2), ~ (1, 3),~ (2,4) \}. \end{equation*}
The domain of \(f\) is \(\{ 0, ~ 1, ~ 2, ~ 3, ~ 4 \}\) and the range is \(\{ -2, \, -1, ~ 0, ~ 1,~ 2 \}\text{.}\)
The domain of \(f^{-1}\) is \(\{ -2, \, -1, ~ 0, ~ 1,~ 2 \}\) and the range is \(\{ 0, ~ 1, ~ 2, ~ 3, ~ 4 \}\text{.}\)

Exercises Exit Exercises

1.

(a)
Explain what is meant by the phrase "one-to-one" and how you can tell from the graph of the function if the function is one-to-one?
(b)
What is the relationship of the domain and range of a function \(f\) and its inverse function \(f^{-1}\text{?}\)
(c)
What happens when you compose two functions that are inverses of each other?
(d)
Why is \(g(x) = (4x-1)^3\) invertible and \(h(x) = (4x-1)^2\) is not?
(e)
Given \(m(x) = 19 + (-3x+1)^5\text{,}\) find \(m^{-1}\text{.}\)

Reflection Reflection

1.

On a scale of 1-5, how are you feeling with the concepts related to the graphical behaviors of functions?